Math Problem Statement

Solve the following absolute value inequality. StartAbsoluteValue 14 x EndAbsoluteValueless than or equals7

Solution

The given absolute value inequality is:

14x7|14x| \leq 7

To solve this, we need to consider the definition of absolute value. The inequality AB|A| \leq B can be rewritten as:

BAB-B \leq A \leq B

In this case, A=14xA = 14x and B=7B = 7, so we have:

714x7-7 \leq 14x \leq 7

Next, we solve for xx by dividing all parts of the inequality by 14:

71414x14714\frac{-7}{14} \leq \frac{14x}{14} \leq \frac{7}{14}

Simplifying this, we get:

12x12-\frac{1}{2} \leq x \leq \frac{1}{2}

So, the solution to the inequality is:

x[12,12]x \in \left[ -\frac{1}{2}, \frac{1}{2} \right]

This means that xx can be any value between 12-\frac{1}{2} and 12\frac{1}{2}, inclusive.

Would you like any further details or have any questions?

Here are some related questions:

  1. How do you solve absolute value inequalities involving "greater than"?
  2. What is the difference between solving xa|x| \leq a and xa|x| \geq a?
  3. How do you graph the solution to an absolute value inequality on a number line?
  4. Can absolute value inequalities have no solution? If so, when?
  5. How would the inequality change if it was 14x>7|14x| > 7 instead?

Tip: When solving absolute value inequalities, remember that you often need to split the problem into two cases to remove the absolute value.

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Math Problem Analysis

Mathematical Concepts

Algebra
Absolute Value Inequalities

Formulas

Absolute Value Inequality: |A| ≤ B can be rewritten as -B ≤ A ≤ B
Simplification of Inequality

Theorems

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Suitable Grade Level

Grades 8-10