Math Problem Statement

∣x+7∣+2= 4x

Solution

We are given the equation:

x+7+2=4x|x + 7| + 2 = 4x

To solve this, we need to handle the absolute value. The equation splits into two cases based on the definition of absolute value:

Case 1: x+70x + 7 \geq 0 (i.e., x7x \geq -7)

In this case, x+7=x+7|x + 7| = x + 7, so the equation becomes:

x+7+2=4xx + 7 + 2 = 4x

Simplifying:

x+9=4xx + 9 = 4x

Subtract xx from both sides:

9=3x9 = 3x

Now, divide by 3:

x=3x = 3

Since x=37x = 3 \geq -7, this solution is valid for Case 1.

Case 2: x+7<0x + 7 < 0 (i.e., x<7x < -7)

In this case, x+7=(x+7)|x + 7| = -(x + 7), so the equation becomes:

(x+7)+2=4x-(x + 7) + 2 = 4x

Simplifying:

x7+2=4x-x - 7 + 2 = 4x

x5=4x-x - 5 = 4x

Add xx to both sides:

5=5x-5 = 5x

Now, divide by 5:

x=1x = -1

However, this solution does not satisfy the condition x<7x < -7, so it is not valid for Case 2.

Final Solution:

The only valid solution is x=3x = 3.


Would you like more details or further clarification?

Here are 5 related questions you could explore:

  1. What happens when absolute value equations have no solution?
  2. How do we solve absolute value inequalities?
  3. What if the equation had a quadratic term?
  4. How do we graph absolute value functions?
  5. Can we solve systems involving absolute values?

Tip: When solving absolute value equations, always check if your solutions fit the conditions of each case!

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Math Problem Analysis

Mathematical Concepts

Algebra
Absolute Value Equations
Linear Equations

Formulas

|x + 7| = x + 7 when x >= -7
|x + 7| = -(x + 7) when x < -7

Theorems

Absolute Value Theorem
Properties of Linear Equations

Suitable Grade Level

Grades 9-10