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Let's break down the given problem:

1. **The snail takes 10 seconds to move 1 centimeter.**

Now, we can use unit rates to solve the two parts:

### Part 1: How far can the snail move in 2 seconds?

- If the snail moves 1 centimeter in 10 seconds, in 1 second, it moves \( \frac{1}{10} \) cm.
- So, in 2 seconds, it will move:
  \[
  \text{Distance} = 2 \times \frac{1}{10} = \frac{2}{10} = 0.2 \, \text{cm}
  \]

### Part 2: How long will it take the snail to move 2.5 centimeters?

- Again, the snail moves 1 centimeter in 10 seconds.
- To find out how long it takes to move 2.5 cm, we set up a proportion:
  \[
  \frac{1 \, \text{cm}}{10 \, \text{seconds}} = \frac{2.5 \, \text{cm}}{x \, \text{seconds}}
  \]
  Solving for \( x \), we get:
  \[
  x = 2.5 \times 10 = 25 \, \text{seconds}
  \]

So the answers are:
- In 2 seconds, the snail moves **0.2 cm**.
- It takes **25 seconds** for the snail to move 2.5 cm.

Would you like further clarification or details on these steps?

### Related Questions:
1. How long would it take the snail to move 5 centimeters?
2. How far can the snail move in 1 second?
3. If the snail moves 3 centimeters, how much time will it take?
4. What is the snail’s speed in centimeters per second?
5. If the snail speeds up and moves 2 cm in 10 seconds, how long will it take to move 5 cm?

### Tip:
Always try to break down unit rate problems into smaller steps by finding how much happens in 1 second (or any base unit). This helps scale up or down easily!

It takes a snail 10 seconds to move 1 centimeter. How far can the snail move in 2 seconds? How long will it take the snail to move 2.5 centimeters?

Learn how to solve unit rate problems involving time and distance with a snail's movement. This problem explores the concept of unit rates and proportions, suitable for Grades 6-7 students.

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