Math Problem Statement

Solve the following formula for the indicated variable.

C=59(F−32); solve for F

Solution

The given equation is:

C=59(F32)C = \frac{5}{9}(F - 32)

We need to solve for FF.

Step-by-Step Solution:

  1. Multiply both sides by 9 to eliminate the fraction:

9C=5(F32)9C = 5(F - 32)

  1. Divide both sides by 5:

9C5=F32\frac{9C}{5} = F - 32

  1. Add 32 to both sides to isolate FF:

F=9C5+32F = \frac{9C}{5} + 32

Thus, the formula for FF in terms of CC is:

F=9C5+32F = \frac{9C}{5} + 32

Would you like further details or have any other questions?

Here are 5 related questions:

  1. How do we convert Fahrenheit to Celsius using this equation?
  2. What is the physical meaning of the constant 32 in the formula?
  3. How does the fraction 59\frac{5}{9} arise in temperature conversion?
  4. Can you solve this formula for CC when given a specific value of FF?
  5. How does this formula apply to real-world temperature conversions?

Tip: Always check your steps by substituting values back into the equation to verify the solution.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Temperature Conversion

Formulas

C = (5/9)(F - 32)

Theorems

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Suitable Grade Level

Grades 8-10