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The system of equations provided is:

\[
-3y = -3x + 3
\]
\[
y - 3 = 5x
\]

### Step 1: Rearrange both equations into slope-intercept form \( y = mx + b \).

**First equation:**

\[
-3y = -3x + 3
\]

Divide both sides by \(-3\):

\[
y = x - 1
\]

**Second equation:**

\[
y - 3 = 5x
\]

Add 3 to both sides:

\[
y = 5x + 3
\]

### Step 2: Graph both equations or find the point where the two lines intersect.

1. The first equation is \( y = x - 1 \) with slope \( m = 1 \) and \( y \)-intercept \( b = -1 \).
2. The second equation is \( y = 5x + 3 \) with slope \( m = 5 \) and \( y \)-intercept \( b = 3 \).

### Step 3: Solve algebraically by setting the equations equal to each other.

\[
x - 1 = 5x + 3
\]

Solve for \( x \):

\[
x - 5x = 3 + 1
\]

\[
-4x = 4
\]

\[
x = -1
\]

### Step 4: Substitute \( x = -1 \) back into either equation to find \( y \).

Using the first equation \( y = x - 1 \):

\[
y = -1 - 1 = -2
\]

### Conclusion:

The solution to the system is \( (-1, -2) \), so the correct answer is the fourth option: \( (-1, -2) \).

---

Do you want further details or have any questions? Here are some related questions:

1. How do you graph linear equations on a coordinate plane?
2. What are the methods to solve systems of equations (graphing, substitution, elimination)?
3. What does the slope and \( y \)-intercept represent in a linear equation?
4. How do you interpret the point of intersection between two lines?
5. Can a system of equations have no solution or infinite solutions?

**Tip:** When solving by graphing, it's helpful to use the slope and \( y \)-intercept to plot accurate points.

Solve the system of equations by graphing:
-3y = -3x + 3
y - 3 = 5x

This page explains how to solve the system of linear equations -3y = -3x + 3 and y - 3 = 5x by graphing. Learn step-by-step methods to rearrange into slope-intercept form, plot both lines, and find the solution. Perfect for students in Grades 8-10 studying algebra and systems of equations.

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