2x + 3y - z = 7

9x - y + zz = 1

x + 2y + 3z = 5

You have a system of three equations:

1. \( 2x + 3y - z = 7 \)
2. \( 9x - y + z^2 = 1 \)
3. \( x + 2y + 3z = 5 \)

It looks like there is a typo in the second equation with the term \( zz \). Could you confirm if you meant:

- \( z^2 \) (the square of \( z \)), or
- \( z \) (a single \( z \) term)?

Once I have clarification, I can proceed with solving the system for you.

2x + 3y - z = 7
9x - y + zz = 1
x + 2y + 3z = 5

This guide provides a step-by-step solution to a system of three equations: 2x + 3y - z = 7, 9x - y + zz = 1, and x + 2y + 3z = 5. Clarify whether the term zz is quadratic, and learn how to solve using algebraic techniques. Suitable for Grades 9-12 students.

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