Math Problem Statement

slove this equation and find c2,c3,c4 and etc, when we have these r1=0.01, r2=0.02, r3=0.03, m=1.25610^-6 ,n=10010^-7,l=1*10^-7, j1=318471, j2=-127388, c1=0

-mnj1((r1)^2/4)+c1ln(r1)+c2 =c3ln(r1)+c4, c3ln(r2)+c4= -mnj2*((r2)^2/4)+c5ln(r2)+c6, -mnj2*((r3)^2/4)+c5ln(r3)+c6 =c7ln(r3)+c8, ((j1r1)/2) – ((c1)/(nmr1))= - ((c3)/(mlr1)), -((c3)/(mlr2))= ((j2r2)/2) – ((c5)/(nmr2), ((j2r3)/2) – ((c5)/(nmr3))= - ((c7)/(lmr3)), -nmj2((0.025^2)/4)+c5ln(0.025)+c6=0

Solution

To solve this system of equations, we need to break it into manageable parts. The system involves parameters r1,r2,r3,m,n,l,j1,j2,c1r_1, r_2, r_3, m, n, l, j_1, j_2, c_1, and constants c2,c3,c4,c_2, c_3, c_4, \ldots that we need to determine. The equations are structured as follows:

System of Equations

  1. mnj1r124+c1ln(r1)+c2=c3ln(r1)+c4-mnj_1 \frac{r_1^2}{4} + c_1 \ln(r_1) + c_2 = c_3 \ln(r_1) + c_4
  2. c3ln(r2)+c4=mnj2r224+c5ln(r2)+c6c_3 \ln(r_2) + c_4 = -mnj_2 \frac{r_2^2}{4} + c_5 \ln(r_2) + c_6
  3. mnj2r324+c5ln(r3)+c6=c7ln(r3)+c8-mnj_2 \frac{r_3^2}{4} + c_5 \ln(r_3) + c_6 = c_7 \ln(r_3) + c_8
  4. j1r12c1nmr1=c3mlr1\frac{j_1 r_1}{2} - \frac{c_1}{nmr_1} = -\frac{c_3}{mlr_1}
  5. c3mlr2=j2r22c5nmr2-\frac{c_3}{mlr_2} = \frac{j_2 r_2}{2} - \frac{c_5}{nmr_2}
  6. j2r32c5nmr3=c7lmr3\frac{j_2 r_3}{2} - \frac{c_5}{nmr_3} = -\frac{c_7}{lmr_3}
  7. nmj2(0.025)24+c5ln(0.025)+c6=0-nmj_2 \frac{(0.025)^2}{4} + c_5 \ln(0.025) + c_6 = 0

Known Values

  • r1=0.01r_1 = 0.01, r2=0.02r_2 = 0.02, r3=0.03r_3 = 0.03
  • m=1.256×106m = 1.256 \times 10^{-6}, n=100×107n = 100 \times 10^{-7}, l=1×107l = 1 \times 10^{-7}
  • j1=318471j_1 = 318471, j2=127388j_2 = -127388, c1=0c_1 = 0

Strategy to Solve

We will:

  1. Substitute known values into the equations to simplify.
  2. Solve the equations sequentially, starting with the simpler ones.
  3. Use consistency between equations to find c2,c3,c4,c_2, c_3, c_4, \ldots.

Let’s begin by substituting the given parameters into the equations. Define the given constants import sympy as sp

Known values

r1, r2, r3 = 0.01, 0.02, 0.03 m = 1.256e-6 n = 100e-7 l = 1e-7 j1, j2 = 318471, -127388 c1 = 0

Declare symbolic variables for unknowns

c2, c3, c4, c5, c6, c7, c8 = sp.symbols('c2 c3 c4 c5 c6 c7 c8')

Define the equations

eq1 = -m * n * j1 * (r12 / 4) + c1 * sp.ln(r1) + c2 - c3 * sp.ln(r1) - c4 eq2 = c3 * sp.ln(r2) + c4 + m * n * j2 * (r22 / 4) - c5 * sp.ln(r2) - c6 eq3 = -m * n * j2 * (r32 / 4) + c5 * sp.ln(r3) + c6 - c7 * sp.ln(r3) - c8 eq4 = (j1 * r1 / 2) - (c1 / (n * m * r1)) + (c3 / (m * l * r1)) eq5 = -(c3 / (m * l * r2)) - (j2 * r2 / 2) + (c5 / (n * m * r2)) eq6 = (j2 * r3 / 2) - (c5 / (n * m * r3)) + (c7 / (l * m * r3)) eq7 = -n * m * j2 * (0.0252 / 4) + c5 * sp.ln(0.025) + c6

Solve the system of equations

solutions = sp.solve([eq1, eq2, eq3, eq4, eq5, eq6, eq7], [c2, c3, c4, c5, c6, c7, c8]) solutionsThe solutions for the unknown coefficients are:

c_2 & = 1.2742 \times 10^{-10}, \\ c_3 & = -1.9999 \times 10^{-12}, \\ c_4 & = 1.8211 \times 10^{-11}, \\ c_5 & = -5.1999 \times 10^{-10}, \\ c_6 & = -2.1682 \times 10^{-9}, \\ c_7 & = 1.9999 \times 10^{-12}, \\ c_8 & = 2.2206 \times 10^{-11}. \end{aligned}$$ These values satisfy the given equations with the provided parameters. Would you like a detailed step-by-step explanation for the solution process? ### Related Questions: 1. How are logarithmic terms handled when solving such equations? 2. What physical scenarios could involve equations like these? 3. How does the small value of $$m$$ affect the behavior of the system? 4. Can such systems be solved numerically without symbolic computation? 5. What is the role of $$c_1 = 0$$ in simplifying the equations? ### Tip: When working with logarithmic equations, always check the domain of the logarithmic terms to ensure that the arguments are positive.

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Math Problem Analysis

Mathematical Concepts

System of Equations
Logarithmic Equations
Algebraic Manipulations
Symbolic Computation

Formulas

Logarithmic properties: ln(a) + ln(b) = ln(ab), ln(a) - ln(b) = ln(a/b)
General equation of a linear system: Ax + By + C = 0
Substitution and elimination methods for solving systems

Theorems

Properties of Logarithms
Linear Independence of Equations

Suitable Grade Level

Undergraduate Mathematics or Advanced High School