Math Problem Statement

Solve the system of equations: x/2 - y/3 = 2 and x/4 + y/2 = 3.

Solution

The problem asks for the solution set of the following system of equations:

\frac{x}{2} - \frac{y}{3} = 2 \\ \frac{x}{4} + \frac{y}{2} = 3 \end{cases}$$ Let's solve this system step-by-step. ### Step 1: Solve the first equation The first equation is: $$\frac{x}{2} - \frac{y}{3} = 2$$ Multiply the entire equation by 6 to eliminate the denominators: $$6 \times \left(\frac{x}{2} - \frac{y}{3}\right) = 6 \times 2$$ This simplifies to: $$3x - 2y = 12$$ So, the first equation becomes: $$3x - 2y = 12 \quad (1)$$ ### Step 2: Solve the second equation The second equation is: $$\frac{x}{4} + \frac{y}{2} = 3$$ Multiply the entire equation by 4 to eliminate the denominators: $$4 \times \left(\frac{x}{4} + \frac{y}{2}\right) = 4 \times 3$$ This simplifies to: $$x + 2y = 12$$ So, the second equation becomes: $$x + 2y = 12 \quad (2)$$ ### Step 3: Solve the system Now, we have the system: $$\begin{cases} 3x - 2y = 12 \\ x + 2y = 12 \end{cases}$$ Add both equations to eliminate $$y$$: $$(3x - 2y) + (x + 2y) = 12 + 12$$ This simplifies to: $$4x = 24$$ So, $$x = 6$$ ### Step 4: Substitute $$x = 6$$ into the second equation Substitute $$x = 6$$ into equation (2): $$6 + 2y = 12$$ This simplifies to: $$2y = 6 \quad \Rightarrow \quad y = 3$$ ### Solution The solution set is: $$(x, y) = (6, 3)$$ --- Do you have any questions, or would you like further details on any step? Here are 5 related questions you can explore: 1. How can we solve systems of equations using substitution? 2. What is the method of elimination for solving linear systems? 3. How can you solve systems of equations with three variables? 4. What are consistent, inconsistent, and dependent systems? 5. How can matrices be used to solve systems of equations? **Tip**: Multiplying both sides of an equation by a common denominator helps eliminate fractions and simplifies solving equations.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Simultaneous Equations
Algebra

Formulas

Elimination Method
Substitution Method

Theorems

System of Linear Equations

Suitable Grade Level

Grades 9-12