Math Problem Statement

2x+y-z=9 βˆ’π‘₯+6𝑦+22=βˆ’17βˆ’x+6y+22=βˆ’17

5π‘₯+7𝑦+2=45x+7y+2=4

Solution

It seems like the equations have some repeated and misformatted parts. Based on the patterns, I assume you intended a system of three equations. I'll simplify the equations as best I can interpret them. Here's what the system seems like:

  1. 2x+yβˆ’z=92x + y - z = 9
  2. βˆ’x+6y+22=βˆ’17-x + 6y + 22 = -17
  3. 5x+7y+2=45x + 7y + 2 = 4

Let's simplify each equation:

Simplified Equations:

  1. From 2x+yβˆ’z=92x + y - z = 9 β€” (Equation 1)

  2. From βˆ’x+6y+22=βˆ’17-x + 6y + 22 = -17, simplify: βˆ’x+6y=βˆ’39-x + 6y = -39 β€” (Equation 2)

  3. From 5x+7y+2=45x + 7y + 2 = 4, simplify: 5x+7y=25x + 7y = 2 β€” (Equation 3)

Now we have:

  1. 2x+yβˆ’z=92x + y - z = 9
  2. βˆ’x+6y=βˆ’39-x + 6y = -39
  3. 5x+7y=25x + 7y = 2

Solving the System of Equations

Let's solve these equations step by step.

  1. From Equation 2:
    βˆ’x+6y=βˆ’39β€…β€ŠβŸΉβ€…β€Šx=6y+39-x + 6y = -39 \implies x = 6y + 39

  2. Substitute x=6y+39x = 6y + 39 into Equation 3:

    5(6y+39)+7y=25(6y + 39) + 7y = 2

    30y+195+7y=230y + 195 + 7y = 2

    37y+195=237y + 195 = 2

    37y=2βˆ’19537y = 2 - 195

    37y=βˆ’193β€…β€ŠβŸΉβ€…β€Šy=βˆ’19337=βˆ’19337β‰ˆβˆ’5.21637y = -193 \implies y = -\frac{193}{37} = -\frac{193}{37} \approx -5.216

  3. Substitute y=βˆ’19337y = -\frac{193}{37} back into the expression for xx:

    x=6(βˆ’19337)+39x = 6\left(-\frac{193}{37}\right) + 39

    x=βˆ’115837+39x = -\frac{1158}{37} + 39

    x=βˆ’115837+144337=28537=7.703x = -\frac{1158}{37} + \frac{1443}{37} = \frac{285}{37} = 7.703

  4. Finally, use Equation 1 to find zz:

    Substitute x=28537x = \frac{285}{37} and y=βˆ’19337y = -\frac{193}{37}:

    2(28537)+(βˆ’19337)βˆ’z=92\left(\frac{285}{37}\right) + \left(-\frac{193}{37}\right) - z = 9

    Simplify:

    57037βˆ’19337βˆ’z=9\frac{570}{37} - \frac{193}{37} - z = 9

    37737βˆ’z=9\frac{377}{37} - z = 9

    βˆ’z=9βˆ’37737-z = 9 - \frac{377}{37}

    βˆ’z=33337βˆ’37737=βˆ’4437-z = \frac{333}{37} - \frac{377}{37} = -\frac{44}{37}

    z=4437β‰ˆ1.189z = \frac{44}{37} \approx 1.189

Solution:

x=28537,y=βˆ’19337,z=4437x = \frac{285}{37}, \quad y = -\frac{193}{37}, \quad z = \frac{44}{37}

Would you like more details, or do you have any questions?

Here are 5 related questions to expand on this:

  1. How can we verify solutions using substitution?
  2. How do we handle systems where the variables are not aligned?
  3. What other methods can be used to solve this system?
  4. How does the value of zz affect xx and yy?
  5. Can these equations represent real-world problems?

Tip: When working with systems of equations, it's important to double-check each step to ensure accuracy, especially when substituting values!