https://file.aiquickdraw.com/mathbot/file/17256472481538phy8jj9.jpg

To solve the system of equations given in the image:

\[
\begin{aligned}
y &= 2x + 48 \quad \text{(Equation 1)}\\
y &= 9x + 13 \quad \text{(Equation 2)}
\end{aligned}
\]

We can use the substitution or elimination method. Here, I'll use the substitution method since both equations are already solved for \(y\).

### Step 1: Set the equations equal to each other
Since both expressions are equal to \(y\), we can set them equal to each other:

\[
2x + 48 = 9x + 13
\]

### Step 2: Solve for \(x\)
Subtract \(2x\) from both sides:

\[
48 = 7x + 13
\]

Subtract 13 from both sides:

\[
35 = 7x
\]

Now, divide by 7:

\[
x = 5
\]

### Step 3: Solve for \(y\)
Substitute \(x = 5\) back into one of the original equations. I'll use Equation 1:

\[
y = 2(5) + 48 = 10 + 48 = 58
\]

### Final Solution:
\[
x = 5, \quad y = 58
\]

Would you like more details, or do you have any questions about this solution?

Here are 5 related questions:
1. How can you verify the solution of a system of equations?
2. What other methods can be used to solve a system of linear equations?
3. How do you solve a system of equations graphically?
4. What is the importance of checking the solution in both equations?
5. How does substitution compare to elimination in terms of solving systems?

**Tip:** Always substitute the solution back into the original equations to verify your answers are correct.

Solve the system of equations: y = 2x + 48 and y = 9x + 13.

Learn how to solve the system of linear equations y = 2x + 48 and y = 9x + 13 using the substitution method. This step-by-step solution covers essential algebra concepts for students in Grades 7-10.

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