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Let's solve the system of equations provided:

1. \( 2x + y = 7 \)
2. \( x - y = 2 \)

We will solve this algebraically rather than graphically for efficiency.

### Step 1: Solve the second equation for \( y \)
\[
x - y = 2 \implies y = x - 2
\]

### Step 2: Substitute \( y = x - 2 \) into the first equation
\[
2x + (x - 2) = 7
\]
Simplifying:
\[
2x + x - 2 = 7
\]
\[
3x - 2 = 7
\]
\[
3x = 9 \implies x = 3
\]

### Step 3: Solve for \( y \)
Substitute \( x = 3 \) into \( y = x - 2 \):
\[
y = 3 - 2 = 1
\]

### Solution:
The solution is \( (x, y) = (3, 1) \).

Therefore, the correct answer is **b. (3, 1)**.

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Would you like more details or have any questions?

Here are some related questions to expand on this:

1. What method can be used to solve systems of equations algebraically besides substitution?
2. How can you graphically determine the solution to a system of equations?
3. What is the elimination method in solving systems of equations?
4. What is the geometric interpretation of a solution to a system of two linear equations?
5. How do you know when a system of equations has no solution?

**Tip:** When solving systems of equations graphically, the solution is the point where the lines intersect.

Solve the system of equations below graphically and write your answer in the form (x, y).

2x + y = 7
x - y = 2

Learn how to solve the system of equations 2x + y = 7 and x - y = 2 using substitution. This problem covers algebraic methods for solving systems of linear equations and is suitable for students in Grades 8-10.

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