Math Problem Statement

Solve this system of differential equations: dS/dt = -\beta S I dI/dt = \beta S I

Solution

The given system of differential equations is:

dSdt=βSI\frac{dS}{dt} = -\beta S I dIdt=βSI\frac{dI}{dt} = \beta S I

Solution:

  1. Sum of the equations: dSdt+dIdt=βSI+βSI=0\frac{dS}{dt} + \frac{dI}{dt} = -\beta S I + \beta S I = 0 This implies: d(S+I)dt=0\frac{d(S + I)}{dt} = 0 Therefore, S+IS + I is a constant, say CC.

    S(t)+I(t)=CS(t) + I(t) = C

  2. Express SS in terms of II: S(t)=CI(t)S(t) = C - I(t)

  3. Substitute into one of the original equations: Substitute S(t)=CI(t)S(t) = C - I(t) into dIdt=βSI\frac{dI}{dt} = \beta S I: dIdt=β(CI)I\frac{dI}{dt} = \beta (C - I) I This simplifies to: dIdt=βCIβI2\frac{dI}{dt} = \beta C I - \beta I^2

  4. Separate the variables: dII(CI)=βdt\frac{dI}{I(C - I)} = \beta dt

  5. Partial fraction decomposition: 1I(CI)=1C(1I+1CI)\frac{1}{I(C - I)} = \frac{1}{C} \left(\frac{1}{I} + \frac{1}{C-I}\right) So the equation becomes: 1C(1I+1CI)dI=βdt\frac{1}{C} \left(\frac{1}{I} + \frac{1}{C - I}\right) dI = \beta dt Integrating both sides: 1C(lnIlnCI)=βt+constant\frac{1}{C} \left(\ln|I| - \ln|C - I|\right) = \beta t + \text{constant} ln(ICI)=βCt+constant\ln\left(\frac{I}{C - I}\right) = \beta C t + \text{constant} ICI=AeβCt\frac{I}{C - I} = A e^{\beta C t} where AA is a constant that can be determined by initial conditions.

    Solving for I(t)I(t): I(t)=ACeβCt1+AeβCtI(t) = \frac{A C e^{\beta C t}}{1 + A e^{\beta C t}} where AA depends on the initial condition I(0)I(0).

    Knowing S(t)=CI(t)S(t) = C - I(t), we have: S(t)=C1+AeβCtS(t) = \frac{C}{1 + A e^{\beta C t}}

Conclusion:

The solutions are: S(t)=C1+AeβCtS(t) = \frac{C}{1 + A e^{\beta C t}} I(t)=ACeβCt1+AeβCtI(t) = \frac{A C e^{\beta C t}}{1 + A e^{\beta C t}}

where AA and CC are constants determined by the initial conditions.

Would you like more details on any step, or have any questions?

Here are some related questions:

  1. What are the biological interpretations of S(t)S(t) and I(t)I(t)?
  2. How do initial conditions affect the behavior of S(t)S(t) and I(t)I(t)?
  3. Can this system be used to model any real-world scenarios?
  4. What happens to S(t)S(t) and I(t)I(t) as tt approaches infinity?
  5. How would the solution change if the differential equations had additional terms, such as a recovery rate?

Tip: Understanding how constants are determined by initial conditions is crucial in solving differential equations applied to real-world scenarios.

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Math Problem Analysis

Mathematical Concepts

Differential Equations
Epidemiology
Mathematical Modeling

Formulas

Differential equations: dS/dt = -βSI, dI/dt = βSI

Theorems

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Suitable Grade Level

Advanced Undergraduate