Solve for x:
square root of, 4, x, plus, 25, end square root, minus, 5, equals, minus, 2
4x+25
​	
 −5=
−2

We are given the equation:

\[
\sqrt{4x + 25} - 5 = -2
\]

### Step 1: Isolate the square root term
Add 5 to both sides to eliminate the constant term on the left-hand side:

\[
\sqrt{4x + 25} = -2 + 5
\]

\[
\sqrt{4x + 25} = 3
\]

### Step 2: Square both sides
To eliminate the square root, square both sides of the equation:

\[
(\sqrt{4x + 25})^2 = 3^2
\]

\[
4x + 25 = 9
\]

### Step 3: Solve for \(x\)
Subtract 25 from both sides:

\[
4x = 9 - 25
\]

\[
4x = -16
\]

Now, divide by 4:

\[
x = \frac{-16}{4}
\]

\[
x = -4
\]

### Final Answer:
\[
x = -4
\]

Would you like further details or have any questions?

Here are 5 related questions for practice:
1. Solve \( \sqrt{3x + 10} - 4 = 5 \).
2. Solve \( \sqrt{5x + 7} = 4 \).
3. Solve \( \sqrt{9x - 1} = 6 \).
4. Solve \( \sqrt{2x + 16} - 3 = 1 \).
5. Solve \( \sqrt{7x + 25} = 5 \).

**Tip:** Always check if your answer works by substituting it back into the original equation to ensure no extraneous solutions.

Solve for x: square root of 4x plus 25 end square root minus 5 equals minus 2

Learn how to solve the square root equation √(4x + 25) - 5 = -2 step-by-step. This problem involves isolating the square root and solving a linear equation. Ideal for students in Grades 8-10.

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