Math Problem Statement

Solve the simultaneous equations using an algebraic method: x + 2y = 13 3x + y = 24

Solution

To solve the simultaneous equations:

x + 2y = 13 \tag{1} 3x + y = 24 \tag{2}

Step 1: Solve one equation for one variable

From equation (1), express xx in terms of yy: x = 13 - 2y \tag{3}

Step 2: Substitute into the second equation

Substitute x=132yx = 13 - 2y from (3) into equation (2): 3(132y)+y=243(13 - 2y) + y = 24

Simplify: 396y+y=2439 - 6y + y = 24 395y=2439 - 5y = 24

Rearrange to solve for yy: 5y=2439-5y = 24 - 39 5y=15-5y = -15 y=3y = 3

Step 3: Substitute y=3y = 3 back into equation (3)

Substitute y=3y = 3 into x=132yx = 13 - 2y: x=132(3)x = 13 - 2(3) x=136x = 13 - 6 x=7x = 7

Final Solution:

x=7,y=3x = 7, \, y = 3

Would you like a more detailed breakdown of any of the steps? Here are some related questions:

  1. What are other methods for solving simultaneous equations (e.g., substitution vs. elimination)?
  2. Can simultaneous equations always have a unique solution?
  3. How can these equations be visualized graphically?
  4. What happens if the equations describe parallel lines?
  5. How do we approach systems with more than two equations?

Tip: Always check your solution by substituting the values back into the original equations!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Simultaneous Equations
Linear Equations

Formulas

Substitution method for solving simultaneous equations

Theorems

No specific theorems directly apply, but foundational algebra principles are used.

Suitable Grade Level

Grades 8-10