Math Problem Statement

According to a certain​ organization's rules, the maximum sail area S for a boat with length L​ (in meters) and displacement D​ (in cubic​ meters) is determined by the equation given below. Upper L plus 1.25 Upper S Superscript one half Baseline minus 9.8 Upper D Superscript one third Baseline equals 16.296 Find S for a boat with length 20.52 m and displacement 17.72 mcubed.

Solution

The equation given is:

L+1.25S9.8D13=16.296L + 1.25 \cdot \sqrt{S} - 9.8 \cdot D^{\frac{1}{3}} = 16.296

You need to find SS when the length L=20.52mL = 20.52 \, \text{m} and the displacement D=17.72m3D = 17.72 \, \text{m}^3.

Let's substitute the known values of LL and DD into the equation and solve for SS.

20.52+1.25S9.8(17.72)13=16.29620.52 + 1.25 \cdot \sqrt{S} - 9.8 \cdot (17.72)^{\frac{1}{3}} = 16.296

First, calculate 9.8(17.72)139.8 \cdot (17.72)^{\frac{1}{3}}, and then solve for SS. I'll handle the calculations step by step.The sail area SS for the boat with a length of 20.52 meters and a displacement of 17.72 cubic meters is approximately 291.05m2291.05 \, \text{m}^2.

Would you like more details on the steps, or do you have any questions?

Here are some related questions to expand your understanding:

  1. How does the displacement DD affect the sail area in the equation?
  2. What happens to the sail area SS if the length of the boat is increased?
  3. Can you solve for LL if the sail area SS and displacement DD are known?
  4. How would the formula change if a different coefficient is used for S1/2S^{1/2}?
  5. What is the physical meaning of the cube root of displacement DD?

Tip: When solving for variables under a square root, it's important to isolate the square root term before squaring both sides to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Algebra
Radical Equations
Cubic Roots

Formulas

L + 1.25 * sqrt(S) - 9.8 * D^(1/3) = 16.296
sqrt(S) = (16.296 - L + 9.8 * D^(1/3)) / 1.25

Theorems

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Suitable Grade Level

Grades 10-12