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The problem presented in the image asks to find the mass of apples picked in a week, given the total mass of pears and a ratio between the mass of apples and pears.

### Problem:

- The total mass of pears picked was **18540 kg**.
- The ratio of the mass of apples to the mass of pears is **13:9**.
  
### Solution:

Let:
- \( a \) be the mass of apples (in kg),
- \( p = 18540 \) kg be the mass of pears,
- The ratio is \( \frac{a}{p} = \frac{13}{9} \).

We can express this ratio as:
\[
\frac{a}{18540} = \frac{13}{9}
\]

To find the mass of apples (\( a \)), multiply both sides of the equation by 18540:
\[
a = \frac{13}{9} \times 18540
\]

Now, I'll calculate the value of \( a \).The mass of apples picked that week is **26,780 kg**.

Would you like further explanation or details on this calculation? Here are a few related questions to expand on this topic:

1. How do you derive the formula for proportional ratios?
2. What are some other practical examples of ratio problems in agriculture?
3. How would the mass of apples change if the ratio were reversed (9:13)?
4. Can ratios always be expressed as fractions?
5. How would you calculate the total mass of fruits picked (apples + pears) in this scenario?

**Tip:** When solving ratio problems, always ensure the units are consistent, especially when the ratio is between two different measurements.

One week, the total mass of pears picked was 18,540 kg. The ratio mass of apples: mass of pears is 13:9. Find the mass of apples picked that week.

Find the mass of apples picked in a week using a ratio of 13:9, given the total mass of pears picked is 18,540 kg. This math problem involves ratios and proportions, suitable for students in Grades 6-8.

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