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The solution to the equation \( 2x + 9\sqrt{x} = 5 \) is \( x = \frac{1}{4} \).

Would you like a more detailed explanation of the steps involved in solving this?

Here are some related questions:
1. How do you solve radical equations like this one?
2. What if \( \sqrt{x} \) was replaced with another root, like \( \sqrt[3]{x} \)?
3. How can you check if a solution to an equation is valid?
4. Can this equation have more than one solution?
5. What happens if we change the equation to \( 2x + 9\sqrt{x} = 10 \)?

**Tip:** Always check for extraneous solutions when solving equations with square roots.

Learn how to solve the radical equation 2x + 9√x = 5 with a detailed step-by-step explanation. This problem covers radical and algebraic equation-solving techniques. Suitable for students in Grades 9-10.

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