Math Problem Statement

Solve two quadratic equations (1) x^2 + p x + 4 = 0 and (2) x^2 + 4p x + p = 0. Determine the range of p where the equations have real solutions and combine them for further analysis.

Solution

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Question 2:

It involves two quadratic equations, with pp as a variable parameter:

  1. x2+px+4=0x^2 + p x + 4 = 0
  2. x2+4px+p=0x^2 + 4p x + p = 0

Part (1):

You are asked to analyze the equations to determine the values of pp for which the real solutions exist and explore how those solutions vary with pp.

Part (2):

You are asked to eliminate one variable, likely combining the two equations to derive additional conditions on pp.

Part (3):

This part involves the discriminant of the quadratic equations, which helps in determining the conditions for real solutions based on pp's value.


Would you like a detailed step-by-step solution for this problem?

Here are some related questions you could explore:

  1. How do we calculate the discriminant of a quadratic equation?
  2. What does it mean when the discriminant is positive, negative, or zero?
  3. How can we solve for the roots of a quadratic equation using the quadratic formula?
  4. What conditions ensure that two quadratic equations have real roots?
  5. How can you apply Vieta’s formulas to relate the coefficients and roots?

Tip: The discriminant Δ=b24ac\Delta = b^2 - 4ac helps determine the nature of roots for quadratic equations.

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Math Problem Analysis

Mathematical Concepts

Quadratic Equations
Discriminants
Real Solutions

Formulas

Quadratic Equation Formula: ax^2 + bx + c = 0
Discriminant Formula: Δ = b^2 - 4ac

Theorems

Discriminant Theorem
Quadratic Formula

Suitable Grade Level

Grades 9-12