Math Problem Statement

Solve the Quadratic Equation: Solve x^2+2x-3=0 by factoring

Solution

To solve the quadratic equation x2+2x3=0x^2 + 2x - 3 = 0 by factoring, follow these steps:

  1. Set the equation to zero: The equation is already in the standard form ax2+bx+c=0ax^2 + bx + c = 0, where a=1a = 1, b=2b = 2, and c=3c = -3.

  2. Factor the quadratic expression: We need to find two numbers that multiply to c=3c = -3 and add to b=2b = 2.

    • The factors of 3-3 that add up to 22 are 33 and 1-1.
  3. Write the equation in factored form: x2+2x3=(x+3)(x1)=0x^2 + 2x - 3 = (x + 3)(x - 1) = 0

  4. Solve for xx: Set each factor equal to zero. x+3=0orx1=0x + 3 = 0 \quad \text{or} \quad x - 1 = 0

    Solving these gives: x=3orx=1x = -3 \quad \text{or} \quad x = 1

So, the solutions to the equation x2+2x3=0x^2 + 2x - 3 = 0 are x=3x = -3 and x=1x = 1.

Would you like more details or have any questions?


Here are 5 related questions:

  1. How do you solve quadratic equations using the quadratic formula?
  2. Can every quadratic equation be factored?
  3. How do you complete the square for a quadratic equation?
  4. What are the different methods to solve quadratic equations?
  5. How can you use the graph of a quadratic function to find its roots?

Tip: When factoring quadratic equations, always check if the equation can be factored easily before using more complex methods like the quadratic formula.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Factoring

Formulas

Quadratic equation ax^2 + bx + c = 0

Theorems

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Suitable Grade Level

Grades 7-9