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The equation provided is:

\[
3(x^2 + 1) = 4(x + 1)
\]

We are asked to solve this equation using the completing the square method. Let's go through the steps:

### Step 1: Expand both sides
First, expand both sides of the equation:

\[
3(x^2 + 1) = 4(x + 1)
\]

Expanding both sides:

\[
3x^2 + 3 = 4x + 4
\]

### Step 2: Rearrange the terms
Move all terms to one side to set the equation to zero:

\[
3x^2 + 3 - 4x - 4 = 0
\]

Simplify:

\[
3x^2 - 4x - 1 = 0
\]

### Step 3: Divide by 3 (if necessary)
If we want the coefficient of \(x^2\) to be 1 for easier completing the square, divide the entire equation by 3:

\[
x^2 - \frac{4}{3}x - \frac{1}{3} = 0
\]

### Step 4: Complete the square
To complete the square, we need to adjust the quadratic and linear terms. Take the coefficient of \(x\), which is \(-\frac{4}{3}\), divide it by 2, and square it:

\[
\left(\frac{-\frac{4}{3}}{2}\right)^2 = \left(\frac{-2}{3}\right)^2 = \frac{4}{9}
\]

Now add and subtract \(\frac{4}{9}\) to the equation:

\[
x^2 - \frac{4}{3}x + \frac{4}{9} - \frac{4}{9} - \frac{1}{3} = 0
\]

This can be written as:

\[
\left(x - \frac{2}{3}\right)^2 - \frac{4}{9} - \frac{1}{3} = 0
\]

### Step 5: Simplify
Now combine the constant terms:

\[
-\frac{4}{9} - \frac{1}{3} = -\frac{4}{9} - \frac{3}{9} = -\frac{7}{9}
\]

So the equation becomes:

\[
\left(x - \frac{2}{3}\right)^2 = \frac{7}{9}
\]

### Step 6: Solve for \(x\)
Take the square root of both sides:

\[
x - \frac{2}{3} = \pm \sqrt{\frac{7}{9}} = \pm \frac{\sqrt{7}}{3}
\]

Now solve for \(x\):

\[
x = \frac{2}{3} \pm \frac{\sqrt{7}}{3}
\]

Thus, the two solutions are:

\[
x = \frac{2 + \sqrt{7}}{3} \quad \text{or} \quad x = \frac{2 - \sqrt{7}}{3}
\]

These are the solutions to the equation.

---

Would you like a more detailed explanation on any step? 

Here are 5 related questions for further practice:
1. How do you complete the square for an equation with a different constant on the right-hand side?
2. Can the completing the square method be applied to equations with higher degrees?
3. How does completing the square help derive the quadratic formula?
4. What are the applications of completing the square in real-world problems?
5. How do you solve a quadratic equation using the quadratic formula?

**Tip:** Completing the square is not just a method for solving quadratic equations, it also helps in rewriting equations for conic sections (like circles and parabolas).

Solve the equation by using completing square method: 3(x^2 + 1) = 4(x + 1)

Learn how to solve the quadratic equation 3(x^2 + 1) = 4(x + 1) using the completing the square method. This detailed step-by-step solution involves key algebraic concepts and completing the square, suitable for students in Grades 9-11.

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