To solve the equation \( 2x^2 = 5x \), we can start by rearranging it into a standard quadratic form:

\[
2x^2 - 5x = 0
\]

Now we can factor out \(x\):

\[
x(2x - 5) = 0
\]

This gives us two possible solutions:

1. \( x = 0 \)
2. \( 2x - 5 = 0 \)

Solve the second equation for \(x\):

\[
2x = 5
\]
\[
x = \frac{5}{2}
\]

So, the solutions are:

\[
x = 0 \quad \text{or} \quad x = \frac{5}{2}
\]

Let me know if you want any further explanation!

---

Here are 5 related questions to explore:

1. How do you solve more complex quadratic equations?
2. Can you solve \(x^2 - 4x = 0\)?
3. What does it mean when a quadratic equation has no real solutions?
4. How do you complete the square to solve quadratics?
5. Can a quadratic equation have one repeated root?

**Tip**: Always check if you can factor out terms before using other methods, like completing the square or the quadratic formula.

Learn how to solve the quadratic equation 2x² = 5x by factoring. This problem covers key algebraic concepts, such as rearranging quadratic equations into standard form and using the factoring method. Suitable for students in Grades 8-10.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation