Math Problem Statement

A 140 ml mixture contains mixture of milk and water in the ratio of 9: 5. If x ml mixture is taken out from pack and 10 ml of water is in pack so, the new ratio of milk and water become 7: 5. Then find the quantity of milk taken out from pack?

Solution

Given:

  • Initial volume of the mixture = 140 ml
  • Initial ratio of milk to water = 9:5

First, calculate the initial quantities of milk and water: Total parts=9+5=14\text{Total parts} = 9 + 5 = 14 Volume of milk=914×140=90 ml\text{Volume of milk} = \frac{9}{14} \times 140 = 90 \text{ ml} Volume of water=514×140=50 ml\text{Volume of water} = \frac{5}{14} \times 140 = 50 \text{ ml}

After taking out xx ml of the mixture, 10 ml of water remains, and the new ratio of milk to water becomes 7:5. Let's denote the initial volumes of milk and water as M1M_1 and W1W_1 respectively, and their volumes after taking out xx ml as M2M_2 and W2W_2 respectively.

From the problem: W2=10 mlW_2 = 10 \text{ ml} M2W2=75\frac{M_2}{W_2} = \frac{7}{5}

We can express M2M_2 in terms of W2W_2: M2=75×10=14 mlM_2 = \frac{7}{5} \times 10 = 14 \text{ ml}

When xx ml of the mixture is taken out, the ratio of milk and water in that xx ml should be the same as the initial ratio (9:5). Therefore, the volumes of milk and water in the removed mixture can be calculated using the same initial ratio.

The quantity of mixture left is: 140x ml140 - x \text{ ml}

The amount of milk and water removed should also follow the 9:5 ratio: Volume of milk removedVolume of water removed=95\frac{\text{Volume of milk removed}}{\text{Volume of water removed}} = \frac{9}{5}

If M1M_1 and W1W_1 are the initial volumes of milk and water, respectively, and M2M_2 and W2W_2 are the volumes after removing xx ml of the mixture, then: M2=M1914xM_2 = M_1 - \frac{9}{14}x W2=W1514xW_2 = W_1 - \frac{5}{14}x

Given W2=10W_2 = 10: 50514x=1050 - \frac{5}{14}x = 10 40=514x40 = \frac{5}{14}x x=40×145=112 mlx = \frac{40 \times 14}{5} = 112 \text{ ml}

The volume of milk removed is: 914×112=72 ml\frac{9}{14} \times 112 = 72 \text{ ml}

Thus, the quantity of milk taken out from the pack is 72 ml72 \text{ ml}.

Would you like further details or have any questions?

Here are some related questions:

  1. How do you calculate the new ratio if the quantities are different?
  2. How do you convert ratios into fractions?
  3. What are the steps to solve a ratio problem involving mixtures?
  4. How do you determine the initial quantity from a given ratio and total volume?
  5. How can you set up equations to solve mixture problems?
  6. What happens to the ratio if only one part of the mixture is altered?
  7. How do you handle problems with more complex ratios or multiple steps?
  8. Can you generalize this method for any mixture problem?

Tip: Always check your calculations step-by-step to avoid errors in ratio and proportion problems.

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Math Problem Analysis

Mathematical Concepts

Ratio and Proportion
Mixture Problems
Basic Algebra

Formulas

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Theorems

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Suitable Grade Level

High School