The image contains two problems that involve solving systems of linear equations. Let's go through each problem step by step.

Problem 1:

You are given the following system of equations:

1. $x + 4y = 9$
2. $x + y = 3$

You are asked to find the values of $x$ and $y$ using the elimination method (metode substitusi).

Solution:

1. From the second equation, solve for $x$: $x = 3 - y$

2. Substitute this expression for $x$ in the first equation: $(3 - y) + 4y = 9$

3. Simplify the equation: $3 + 3y = 9$ $3y = 6$ $y = 2$

4. Substitute $y = 2$ back into the equation $x = 3 - y$: $x = 3 - 2 = 1$

So, the solution is $x = 1$ and $y = 2$.

Problem 2:

You are given the following system of equations:

1. $3x - y = 2$
2. $x + y = 6$

You are asked to find the values of $x$ and $y$.

Solution:

1. From the second equation, solve for $y$: $y = 6 - x$

2. Substitute this expression for $y$ in the first equation: $3x - (6 - x) = 2$

3. Simplify the equation: $3x - 6 + x = 2$ $4x - 6 = 2$ $4x = 8$ $x = 2$

4. Substitute $x = 2$ back into the equation $y = 6 - x$: $y = 6 - 2 = 4$

So, the solution is $x = 2$ and $y = 4$.

Do you have any questions or would you like further details?

Here are 5 related questions to further your understanding:

1. How does the elimination method differ from substitution in solving systems of equations?
2. Can a system of linear equations have no solution? If so, under what conditions?
3. What is the graphical interpretation of solving two linear equations?
4. How would you solve the same systems using matrices?
5. How can you check whether your solutions are correct?

Tip: Always substitute your found values of $x$ and $y$ back into the original equations to verify your solution!