Math Problem Statement
Solution
We are given the following system of equations:
Let's solve this step-by-step using substitution or elimination. First, we can eliminate the fractions by multiplying each equation by the least common denominator (LCD) of the fractions in each.
Step 1: Eliminate fractions in the first equation
The first equation is: The LCD of 2 and 3 is 6. Multiply the entire equation by 6: This simplifies to:
Step 2: Eliminate fractions in the second equation
The second equation is: Multiply the entire equation by 5 to eliminate the fractions: This simplifies to:
Step 3: Solve the system of equations
We now have the system:
We can use substitution or elimination to solve this system. Let's use elimination by first multiplying Equation 2 by 2 so that the coefficients of match:
Now subtract Equation 1 from Equation 3:
Step 4: Substitute into one of the original equations
Substitute into Equation 2:
Final Solution:
The solution to the system is:
Would you like more details on any part of the process or have any questions?
Here are some related questions for further exploration:
- How do you solve a system of equations using the substitution method?
- What is the process of solving a system of equations with fractions?
- How does elimination work for solving systems of equations?
- What happens when you have no solution or infinitely many solutions to a system?
- Can systems of equations be solved graphically? How?
Tip: When dealing with fractions in equations, multiplying through by the least common denominator is a quick way to simplify the system.
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Math Problem Analysis
Mathematical Concepts
Algebra
Linear Systems
Fractions
Formulas
Elimination Method
Substitution Method
Theorems
Elimination Theorem for Linear Systems
Suitable Grade Level
Grades 9-12
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