Let's prove that \( y = -2 \) satisfies the equation \( y - \frac{1}{2} = 1 \).

### Given equation:
\[
y - \frac{1}{2} = 1
\]

### Step 1: Add \( \frac{1}{2} \) to both sides
To isolate \( y \), we add \( \frac{1}{2} \) to both sides of the equation:
\[
y - \frac{1}{2} + \frac{1}{2} = 1 + \frac{1}{2}
\]
\[
y = 1 + \frac{1}{2}
\]

### Step 2: Simplify the right-hand side
Now, simplify \( 1 + \frac{1}{2} \):
\[
y = \frac{2}{2} + \frac{1}{2} = \frac{3}{2}
\]

Therefore, the solution to the equation is \( y = \frac{3}{2} \), not \( y = -2 \).

Thus, \( y = -2 \) does **not** satisfy the given equation.

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Would you like further clarification or more details on any step?

Here are 5 related questions:
1. How can we solve equations involving fractions?
2. What happens when adding or subtracting fractions with different denominators?
3. How do we graph linear equations like \( y - \frac{1}{2} = 1 \)?
4. How can you check if a value satisfies an equation?
5. Can equations always be solved using inverse operations?

**Tip:** Always isolate the variable by reversing the operations performed on it!

Learn how to solve the linear equation y - 1/2 = 1 and verify the solution step by step. This problem focuses on solving equations with fractions and isolating the variable, suitable for students in Grades 6-8.

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