https://file.aiquickdraw.com/mathbot/file/17294149893267b51mzlk.jpg

The equation presented in the image is:

\[
x + 15 = 6x
\]

Let's solve for \( x \).

### Step 1: Move all terms involving \( x \) to one side.
Subtract \( x \) from both sides:

\[
x + 15 - x = 6x - x
\]

This simplifies to:

\[
15 = 5x
\]

### Step 2: Solve for \( x \).
Now, divide both sides by 5:

\[
x = \frac{15}{5}
\]

\[
x = 3
\]

So, the solution is:

\[
x = 3
\]

Would you like more details on the steps? Let me know if you have any questions!

Here are 5 related questions you can explore:
1. What happens when you subtract \( 6x \) from both sides instead?
2. Can you create an equation where \( x = -3 \) using similar terms?
3. How do we solve an equation if there are fractions involved?
4. What would change in the solution process if \( x \) was multiplied by a variable on both sides?
5. How would you solve this equation: \( x + 20 = 8x \)?

**Tip:** When solving linear equations, it's helpful to move all variables to one side and constants to the other as early as possible to simplify the solution.

Learn how to solve the linear equation x + 15 = 6x with a clear, step-by-step solution. This problem demonstrates fundamental algebraic techniques, such as isolating variables and solving for x. Perfect for students in Grades 6-8.

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