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The problem is asking to find the cost of each teacup using an appropriate equation. Here’s the breakdown:

**Problem Information:**
- Rebecca buys a teapot costing $18.
- She also buys 4 teacups.
- She spends a total of $42 on the pottery.

We need to find the equation to calculate the cost of each teacup, denoted as $ c $.

### Steps to form the correct equation:
1. **Total cost**: The total amount spent is $42.
2. **Teapot cost**: The teapot costs $18.
3. **Teacup costs**: Let the cost of each teacup be $ c $, and since she bought 4 teacups, the total cost for teacups is $ 4c $.
4. **Equation setup**: The total cost of the teacups and teapot should add up to $42, so the equation will be:
   \[
   18 + 4c = 42
   \]

Now, let’s find which of the options matches this equation. The second option, **$ 4c + 18 = 42 $**, is the correct one.

### Solving the equation:
\[
4c + 18 = 42
\]
Subtract 18 from both sides:
\[
4c = 24
\]
Now divide both sides by 4:
\[
c = 6
\]

So, the cost of each teacup is **$6**.

Would you like further details, or do you have any other questions?

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### Related Questions:
1. What if Rebecca had bought 6 teacups instead of 4? How would the equation change?
2. What would the total cost be if the teapot was $20 instead of $18?
3. How would the equation change if Rebecca spent $50 in total?
4. What if each teacup cost $5? What would be the total cost?
5. How can you check your solution once you've calculated the cost of each teacup?

### Tip:
When solving word problems, always define your variable first and set up the equation based on the relationships given in the problem.

Rebecca chose to paint the largest teapot, which cost $18. She also painted 4 small teacups. Rebecca spent a total of $42 on pottery. What is the cost of each teacup?

Learn how to solve the linear equation 18 + 4c = 42 to find the cost of teacups when given the total pottery cost. This algebra problem is suitable for students in Grades 6-8.

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