To solve for \( r \) in the equation:
\[
r - 3 = 2r + 4
\]

### Step-by-Step Solution:

1. **Isolate the variable** \( r \) on one side by subtracting \( r \) from both sides:  
   \[
   -3 = r + 4
   \]

2. **Subtract 4** from both sides to further isolate \( r \):  
   \[
   -3 - 4 = r
   \]
   \[
   -7 = r
   \]

### Answer:
\[
r = -7
\]

Would you like further details or have any questions about this solution?

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Here are some related questions to explore:
1. How would the solution change if the equation were \( r - 3 = 2r - 4 \)?
2. What steps would you take if the equation were \( 2r - 3 = 4r + 4 \)?
3. Can you solve for \( r \) if the equation were written as \( 3 - r = 4 - 2r \)?
4. How would you approach solving \( r - 3 = 2r + 4r \)?
5. What happens if the variable appears as \( r^2 \) in an equation like \( r^2 - 3 = 2r + 4 \)?

**Tip:** Always start by collecting like terms on one side to simplify the process of isolating the variable.

Explore the step-by-step solution to the linear equation r - 3 = 2r + 4. Learn how to isolate the variable and simplify expressions, covering core algebra concepts for Grades 6-8.

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