Let's solve the equation:

\[
8x + 2 + 4x = -46
\]

### Step 1: Combine like terms
On the left-hand side of the equation, combine the \(8x\) and \(4x\):

\[
(8x + 4x) + 2 = -46 \quad \Rightarrow \quad 12x + 2 = -46
\]

### Step 2: Subtract 2 from both sides
To isolate the term with \(x\), subtract 2 from both sides:

\[
12x = -46 - 2 \quad \Rightarrow \quad 12x = -48
\]

### Step 3: Divide by 12
Now, divide both sides by 12 to solve for \(x\):

\[
x = \frac{-48}{12} \quad \Rightarrow \quad x = -4
\]

Thus, the solution is:

\[
x = -4
\]

Would you like a more detailed explanation or have any other questions?

Here are 5 related questions to expand on this:

1. How would you solve \(7x + 3x + 5 = 15\)?
2. What happens if we change the constant in the equation to another number?
3. How do you solve an equation with variables on both sides?
4. What is the difference between solving linear equations and quadratic equations?
5. Can you solve this equation using graphing methods?

**Tip:** Always check your solution by substituting the value of \(x\) back into the original equation to verify your result.

Discover how to solve the linear equation 8x + 2 + 4x = -46 with a step-by-step explanation. This problem involves key algebraic concepts like combining like terms and properties of equality. Suitable for students in Grades 7-9.

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