To solve the equation \( 8 = 3a - 4 \):

1. Add 4 to both sides to isolate the term with \( a \):
\[
8 + 4 = 3a - 4 + 4
\]
\[
12 = 3a
\]

2. Divide both sides by 3 to solve for \( a \):
\[
\frac{12}{3} = \frac{3a}{3}
\]
\[
a = 4
\]

So, the solution is \( a = 4 \).

Would you like a more detailed explanation or have any further questions?

Here are 5 related questions to further your understanding:
1. What happens if you subtract 4 instead of adding 4 at the beginning?
2. How would the solution change if the equation was \( 8 = 3a + 4 \)?
3. Can you solve \( 8 = 4a - 6 \)?
4. What are the steps to check if your solution is correct?
5. How would you approach solving \( 3a - 4 = 2a + 3 \)?

**Tip:** Always perform the same operation on both sides of an equation to maintain equality!

Learn how to solve the linear equation 8 = 3a - 4 step-by-step. This algebra problem focuses on isolating the variable and solving for 'a', ideal for students in Grades 6-8. Follow the solution to understand how to manage operations on both sides of the equation.

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