Let's solve the equation:

\[
6x + 12 = -20
\]

### Step 1: Subtract 12 from both sides
\[
6x + 12 - 12 = -20 - 12
\]
\[
6x = -32
\]

### Step 2: Divide both sides by 6
\[
x = \frac{-32}{6}
\]

### Step 3: Simplify the fraction
\[
x = \frac{-16}{3}
\]

Thus, the solution is:
\[
x = -\frac{16}{3}
\]

Would you like more details or have any questions?

Here are 5 related questions:
1. How would you solve the equation \(7x + 5 = 3x - 15\)?
2. How do you solve equations involving fractions, like \(\frac{2x}{3} + 5 = 9\)?
3. Can you explain how to check if a solution is correct in an equation?
4. What happens when you have an equation with variables on both sides?
5. How do you solve quadratic equations like \(x^2 + 4x - 5 = 0\)?

**Tip**: Always perform the same operation on both sides of the equation to maintain balance!

Learn how to solve the linear equation 6x + 12 = -20 with a clear, step-by-step explanation. This problem covers key algebraic concepts such as solving linear equations using the balancing method. Suitable for students in Grades 6-8.

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