To solve the equation \( 6 + 3t = 8t - 14 \), follow these steps:

1. **Combine like terms:**
   Move all terms involving \( t \) to one side and constant terms to the other side. Subtract \( 3t \) from both sides of the equation:
   \[
   6 = 8t - 3t - 14
   \]

2. **Simplify:**
   Combine the \( t \) terms on the right side:
   \[
   6 = 5t - 14
   \]

3. **Isolate the variable \( t \):**
   Add 14 to both sides to isolate the term with \( t \):
   \[
   6 + 14 = 5t
   \]
   \[
   20 = 5t
   \]

4. **Solve for \( t \):**
   Divide both sides by 5:
   \[
   t = \frac{20}{5}
   \]
   \[
   t = 4
   \]

So, the solution is \( t = 4 \).

Would you like more details or have any questions about this solution?

Here are 5 related questions to practice:

1. Solve \( 4 + 2x = 6x - 8 \).
2. Solve \( 5 - 3y = 2y + 7 \).
3. Solve \( 10 + 4z = 7z - 2 \).
4. Solve \( 3 + 6m = 9m - 15 \).
5. Solve \( 8 + 5p = 10p - 20 \).

**Tip:** When solving linear equations, always aim to isolate the variable on one side of the equation by performing inverse operations step by step.

Discover how to solve the linear equation 6 + 3t = 8t - 14 with a clear, step-by-step explanation. This solution covers algebraic concepts, including isolating variables and applying inverse operations. Ideal for students in Grades 6-8.

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