Let's solve the equation \( 5x + 11 = 40x - 3 \).

### Step 1: Move all terms involving \( x \) to one side of the equation.
Subtract \( 5x \) from both sides:
\[
11 = 40x - 5x - 3
\]
\[
11 = 35x - 3
\]

### Step 2: Move the constant terms to the other side.
Add 3 to both sides:
\[
11 + 3 = 35x
\]
\[
14 = 35x
\]

### Step 3: Solve for \( x \).
Divide both sides by 35:
\[
x = \frac{14}{35}
\]

Simplify the fraction:
\[
x = \frac{2}{5}
\]

Thus, the solution is \( x = \frac{2}{5} \).

Would you like more details or have any further questions?

Here are 5 related questions to explore:
1. How do you solve an equation with variables on both sides?
2. What happens if you divide by zero in an equation?
3. How do you simplify fractions like \( \frac{14}{35} \)?
4. What is the process of isolating a variable in an equation?
5. How do you check if a solution to an equation is correct?

**Tip:** Always double-check your solutions by substituting the value back into the original equation!

Learn how to solve the linear equation 5x + 11 = 40x - 3 with a step-by-step solution. This problem involves key algebraic concepts such as moving terms with variables, simplifying fractions, and solving for x. Suitable for students in Grades 6-8.

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