Let the unknown number be denoted by $x$.

According to the problem, the sum of four times the number and seven is ten more than the number. This can be written as the following equation:

$4x + 7 = x + 10$

Now, let's solve for $x$:

1. Subtract $x$ from both sides:

$4x - x + 7 = 10$ $3x + 7 = 10$

2. Subtract 7 from both sides:

$3x = 3$

3. Divide both sides by 3:

$x = 1$

Thus, the number is $x = 1$.

Do you want further details or have any questions?

Here are 5 related questions to practice:

1. If the sum of five times a number and eight is equal to twice the number plus fourteen, what is the number?
2. What is the number if three times a number minus four is equal to twice the number plus six?
3. Solve: The sum of seven times a number and nine equals twelve more than four times the number.
4. Find the number if twice the sum of a number and five is equal to the number plus twelve.
5. The difference between four times a number and nine is equal to twice the number plus three. What is the number?

Tip:

When solving equations, remember to always perform the same operation on both sides to maintain equality.