Math Problem Statement

(4 · x) = 0 · x + 4 · 1 = 4

Solution

The equation from the image is:

(4x)=0x+41=4(4 \cdot x) = 0 \cdot x + 4 \cdot 1 = 4

Let's break it down:

  1. 4x=0x+44 \cdot x = 0 \cdot x + 4:
    • The left side is simply 4x4x.
    • The right side simplifies to 0+40 + 4, which is just 44.

Thus, we have:

4x=44x = 4

Now, solve for xx:

x=44=1x = \frac{4}{4} = 1

So, the solution is x=1x = 1.

Would you like further clarification or details? Here are some related questions to deepen understanding:

  1. How do we handle equations where there are multiple terms with xx?
  2. What does multiplying by 0 do in equations, as seen with 0x0 \cdot x?
  3. What steps are involved in simplifying both sides of an equation before solving?
  4. How can we verify the solution once we have x=1x = 1?
  5. What if the equation had no solution or infinite solutions—how would we approach that?

Tip: Always simplify both sides of the equation as much as possible before attempting to solve for the variable.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations

Formulas

Basic equation solving: ax = b

Theorems

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Suitable Grade Level

Grades 6-8