To solve the equation \( 42 + 5t = 8t \), follow these steps:

1. Subtract \( 5t \) from both sides to move the terms involving \( t \) to one side:

\[
42 = 8t - 5t
\]

2. Simplify the right side:

\[
42 = 3t
\]

3. Divide both sides by 3 to solve for \( t \):

\[
t = \frac{42}{3} = 14
\]

So, the solution is \( t = 14 \).

Would you like more details or have any questions? Here are 5 related questions you might consider:

1. What if the equation had been \( 42 + 5t = 9t + 10 \)?
2. How do you solve equations with negative terms, like \( 42 - 5t = 8t \)?
3. Can you solve for \( t \) in an equation like \( 42 + 5t = 10t - 20 \)?
4. How do you solve equations with fractions, such as \( 42 + \frac{5}{2}t = 8t \)?
5. What happens if you had a quadratic equation like \( 5t^2 + 42 = 8t \)?

**Tip**: When solving linear equations, always move terms with the variable to one side first, then simplify step by step.

Learn how to solve the linear equation 42 + 5t = 8t with a step-by-step solution. This problem explores basic algebraic concepts, including moving terms and simplifying equations. Perfect for students in Grades 6-8.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation