Solve for xx.
41, minus, 3, x, equals, 80
41−3x=
80

We are given the equation:

\[
41 - 3x = 80
\]

To solve for \( x \), follow these steps:

1. Subtract 41 from both sides of the equation:
\[
-3x = 80 - 41
\]
\[
-3x = 39
\]

2. Divide both sides of the equation by -3 to isolate \( x \):
\[
x = \frac{39}{-3}
\]
\[
x = -13
\]

Thus, the solution is:

\[
x = -13
\]

Would you like further details or have any questions?

Here are 5 related questions:
1. What is the general method for solving linear equations like this one?
2. How can you check if the solution \( x = -13 \) is correct?
3. How would the solution change if the equation was \( 41 + 3x = 80 \)?
4. Can this equation be solved graphically, and how would that work?
5. What happens if both sides of the equation involve variables?

**Tip**: Always simplify equations step by step to avoid mistakes, especially when negative signs are involved.

Learn how to solve the linear equation 41 - 3x = 80 with a detailed step-by-step solution. This problem covers key algebraic concepts, such as isolating variables and solving for x in simple linear equations. Suitable for students in Grades 6-8.

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