To solve the equation \( 3y + 6 = 12 \), follow these steps:

1. **Subtract 6 from both sides**:
   \[
   3y + 6 - 6 = 12 - 6
   \]
   This simplifies to:
   \[
   3y = 6
   \]

2. **Divide both sides by 3** to isolate \( y \):
   \[
   y = \frac{6}{3}
   \]
   Simplifying:
   \[
   y = 2
   \]

So, the solution is \( y = 2 \).

Would you like more details or have any questions about this?

Here are 5 related questions to further explore this topic:
1. What happens if you change the constant on the right-hand side of the equation?
2. How do you solve \( 2x + 4 = 10 \) in a similar way?
3. Can you solve an equation like \( 4y - 7 = 13 \)?
4. How do you solve equations with fractions, like \( \frac{3y}{2} + 6 = 12 \)?
5. What steps are needed to solve \( 3y + 6 = 0 \)?

**Tip**: Always perform the same operation on both sides of the equation to maintain balance!

Learn how to solve the linear equation 3y + 6 = 12 step by step. This problem covers essential algebraic concepts like isolating variables and using equality principles. Ideal for students in Grades 6-8.

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