Let's solve the equation \( 2x - 3 \cdot (-2) = 16 \).

### Step 1: Simplify the multiplication
The equation is:
\[
2x - 3 \cdot (-2) = 16
\]
Multiplying \(-3\) by \(-2\), we get:
\[
2x + 6 = 16
\]

### Step 2: Subtract 6 from both sides
Now, isolate the term with \(x\):
\[
2x = 16 - 6
\]
\[
2x = 10
\]

### Step 3: Divide by 2
Solve for \(x\):
\[
x = \frac{10}{2}
\]
\[
x = 5
\]

Thus, the solution is \( x = 5 \).

Would you like further details or have any questions about the solution?

Here are 5 related questions:
1. What if the equation was \( 2x - 3(-4) = 16 \)?
2. How do you solve equations with variables on both sides?
3. What is the next step if the equation was \( 2x + 6 = 18 \)?
4. How do you solve equations with fractions like \( \frac{2x}{3} = 4 \)?
5. Can you apply these steps to a quadratic equation like \( 2x^2 - 6 = 16 \)?

**Tip:** Always simplify the terms step by step before isolating the variable for a more accurate solution.

Learn how to solve the linear equation 2x - 3(-2) = 16 step by step. This guide covers simplification, solving for x, and applying key algebraic rules. Suitable for students in Grades 6-8.

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