Let's solve the equation step by step:

Given equation:  
\[
2(2z + 10) = 36
\]

### Step 1: Distribute the \(2\) on the left-hand side.
\[
2 \cdot 2z + 2 \cdot 10 = 36
\]
\[
4z + 20 = 36
\]

### Step 2: Subtract 20 from both sides.
\[
4z = 36 - 20
\]
\[
4z = 16
\]

### Step 3: Divide both sides by 4.
\[
z = \frac{16}{4}
\]
\[
z = 4
\]

So, the solution is \(z = 4\).

Would you like more details or further explanations?

Here are 5 related questions you might find interesting:
1. How do you solve similar equations with fractions?
2. What happens if the equation contains variables on both sides?
3. How do you factor quadratic equations?
4. What are the properties of distributive property in algebra?
5. How do you solve equations involving exponents?

**Tip:** Always simplify expressions inside parentheses before solving for the variable to avoid mistakes.

Learn how to solve the linear equation 2(2z + 10) = 36 with a detailed step-by-step solution. This problem involves the distributive property and basic algebraic operations, suitable for students in Grades 6-8.

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