Let's solve the equation:

\[
-\frac{21}{1} = \frac{11}{2} c - \frac{4}{3}
\]

### Step 1: Multiply both sides of the equation by 6 (the least common denominator of 1, 2, and 3) to eliminate the fractions:

\[
6 \left(-\frac{21}{1}\right) = 6 \left(\frac{11}{2} c\right) - 6 \left(\frac{4}{3}\right)
\]

This gives:

\[
-126 = 33c - 8
\]

### Step 2: Add 8 to both sides:

\[
-126 + 8 = 33c
\]

\[
-118 = 33c
\]

### Step 3: Solve for \(c\) by dividing both sides by 33:

\[
c = \frac{-118}{33}
\]

Thus, the solution is:

\[
c = \frac{-118}{33}
\]

Would you like any further clarification or details?

Here are some related questions you could try:
1. What if the equation was \(\frac{11}{2}c + \frac{4}{3} = -\frac{21}{1}\)?
2. How do you handle solving systems of linear equations with fractions?
3. Can you solve a similar equation involving decimals?
4. How would you solve the equation if it had radicals (square roots)?
5. What steps would you take for an equation with more variables?

**Tip:** Always try to clear fractions by multiplying through by the least common denominator—it simplifies the equation significantly!

Learn how to solve the linear equation 2/1 = 11/2 c - 4/3 step-by-step. This solution involves clearing fractions using the least common denominator (LCD) and solving for the variable. Suitable for students in Grades 8-10.

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