We are given the equation:

\[
-9 = \frac{1}{3}x - 3
\]

Let's solve for \( x \).

### Step 1: Add 3 to both sides to isolate the term with \( x \).

\[
-9 + 3 = \frac{1}{3}x - 3 + 3
\]
\[
-6 = \frac{1}{3}x
\]

### Step 2: Multiply both sides by 3 to eliminate the fraction.

\[
3 \times (-6) = 3 \times \frac{1}{3}x
\]
\[
-18 = x
\]

Thus, the solution is:

\[
x = -18
\]

Would you like a more detailed explanation or have any questions?

Here are some related problems for practice:

1. Solve \( -5 = \frac{1}{4}x - 2 \).
2. Solve \( -7 = \frac{2}{5}x - 1 \).
3. Solve \( 12 = \frac{3}{2}x + 6 \).
4. Solve \( 0 = \frac{5}{6}x - 10 \).
5. Solve \( -15 = \frac{2}{3}x + 4 \).

**Tip:** When dealing with fractions in an equation, multiplying both sides by the denominator is often a good first step to eliminate the fraction.

Learn how to solve the linear equation -9 = (1/3)x - 3 step-by-step. This problem covers essential algebraic concepts, such as isolating variables and eliminating fractions. Ideal for students in Grades 6-8.

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