Math Problem Statement

solve

Solution

The problem in the image involves the infinite series:

n=1(1)n1n6n\sum_{n=1}^{\infty} (-1)^{n-1} \frac{n}{6^n}

Solution:

This is an alternating series, and the general term ana_n is given by:

an=n6na_n = \frac{n}{6^n}

1. Check for Convergence:

To determine if the series converges, we can apply the Alternating Series Test (Leibniz criterion). The series (1)n1an\sum (-1)^{n-1} a_n will converge if:

  • The sequence an=n6na_n = \frac{n}{6^n} is decreasing.
  • limnan=0\lim_{n \to \infty} a_n = 0.

Let's check these conditions:

  1. Monotonic Decreasing:

    • We need to check if an+1<ana_{n+1} < a_n for all nn. an+1=n+16n+1,an=n6na_{n+1} = \frac{n+1}{6^{n+1}}, \quad a_n = \frac{n}{6^n} We compare the ratio: an+1an=n+16n+1n6n=n+16n\frac{a_{n+1}}{a_n} = \frac{\frac{n+1}{6^{n+1}}}{\frac{n}{6^n}} = \frac{n+1}{6n} Since n+16n<1\frac{n+1}{6n} < 1 for all nn, ana_n is indeed decreasing.
  2. Limit to Zero: limnn6n=0\lim_{n \to \infty} \frac{n}{6^n} = 0 As nn grows, the exponential 6n6^n grows much faster than nn, so the limit is zero.

Both conditions are satisfied, so the series converges.

2. Estimate the Sum using the Alternating Series Estimation Theorem:

The Alternating Series Estimation Theorem states that the error RnR_n when approximating the sum SS of the infinite series by the nn-th partial sum SnS_n is less than the magnitude of the first omitted term an+1a_{n+1}.

So, if we want to estimate the sum up to nn terms, the error is less than an+1=n+16n+1a_{n+1} = \frac{n+1}{6^{n+1}}.

3. Graphing the Sequence and the Partial Sums:

The problem asks to graph the sequence of terms an=n6na_n = \frac{n}{6^n} and the partial sums SnS_n. These graphs would typically show:

  • The sequence ana_n decreasing rapidly towards zero.
  • The partial sums SnS_n converging to the actual sum of the series.

To perform these calculations and graph the results, you'd typically use a software tool or graphing calculator. You could also plot the first few terms manually.

Final Answer:

  • Convergence: The series converges.
  • Sum Estimation: Use the Alternating Series Estimation Theorem to approximate the sum SS by calculating partial sums and ensuring the error RnR_n is less than an+1a_{n+1}.

Would you like to see the partial sums calculated for specific terms or need more details on the estimation process?

Here are some related questions:

  1. What is the Alternating Series Test?
  2. How do you determine if a series is monotonic?
  3. Why does limnn6n=0\lim_{n \to \infty} \frac{n}{6^n} = 0?
  4. How does the Alternating Series Estimation Theorem work?
  5. What is the significance of the first omitted term in series estimation?
  6. How do you plot partial sums for a series?
  7. What is the difference between absolute and conditional convergence?
  8. How do exponential functions compare to polynomial growth?

Tip: When estimating the sum of an alternating series, remember that the error is always less than the first omitted term, which can greatly simplify calculations!

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Math Problem Analysis

Mathematical Concepts

Infinite Series
Alternating Series
Convergence Tests

Formulas

Alternating Series Test
Alternating Series Estimation Theorem

Theorems

Leibniz Criterion

Suitable Grade Level

Advanced Undergraduate