Math Problem Statement

If A + D = C + E ,B + 2D = C + 2E ,D - E > E - B And 2D > A + C then A) D > B > C > A > E

C > B > A > D > E

B) A > B > C > D > E

D) C > B > D > A > E

Solution

Given the system of inequalities and equalities:

  1. A+D=C+EA + D = C + E
  2. B+2D=C+2EB + 2D = C + 2E
  3. DE>EBD - E > E - B
  4. 2D>A+C2D > A + C

We need to determine which of the provided orderings (A, B, C, or D) of the variables is consistent with these relationships.

Step-by-step analysis:

1. From the first equation:

A+D=C+EA=C+EDA + D = C + E \quad \Rightarrow \quad A = C + E - D This suggests a direct relationship between AA, CC, EE, and DD, but we don’t yet know which one is larger.

2. From the second equation:

B+2D=C+2EB=C+2E2DB + 2D = C + 2E \quad \Rightarrow \quad B = C + 2E - 2D This equation expresses BB in terms of CC, DD, and EE.

3. From the third inequality:

DE>EBD+B>2ED - E > E - B \quad \Rightarrow \quad D + B > 2E This suggests that D+BD + B is greater than 2E2E, implying that DD and BB are likely larger than EE.

4. From the fourth inequality:

2D>A+CD>A+C22D > A + C \quad \Rightarrow \quad D > \frac{A + C}{2} This inequality implies that DD is greater than the average of AA and CC.

Now let's evaluate the answer choices:

A) D>B>C>A>ED > B > C > A > E

This seems plausible because:

  • From the third inequality, D+B>2ED + B > 2E, which suggests D>ED > E and B>EB > E.
  • From the fourth inequality, D>A+C2D > \frac{A + C}{2}, suggesting D>AD > A and D>CD > C.
  • From the second equation, B=C+2E2DB = C + 2E - 2D, implying that BB could be greater than CC.

Thus, A seems to be a valid solution.

B) A>B>C>D>EA > B > C > D > E

This is not consistent with the inequality 2D>A+C2D > A + C, which suggests that D>AD > A, ruling out this option.

C) C>B>A>D>EC > B > A > D > E

This does not seem to work because it implies C>DC > D, which is inconsistent with the inequality 2D>A+C2D > A + C.

D) C>B>D>A>EC > B > D > A > E

Again, this does not work because it implies C>DC > D, which contradicts 2D>A+C2D > A + C.

Conclusion:

The correct ordering is A) D>B>C>A>ED > B > C > A > E.

Would you like further details on how these inequalities were derived or any clarifications?

Here are some follow-up questions to deepen your understanding:

  1. How do changes in DD affect the order of variables in this system?
  2. Can the inequalities be solved algebraically for exact values of the variables?
  3. How does the condition D+B>2ED + B > 2E influence the overall ranking of the variables?
  4. What would happen to the order if A+C=2DA + C = 2D?
  5. Is there any scenario where two variables could be equal in this system?

Tip: When solving inequalities with multiple variables, always try to isolate one variable and see how the others compare using substitution.

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Math Problem Analysis

Mathematical Concepts

Algebra
Inequalities
Linear Equations

Formulas

A + D = C + E
B + 2D = C + 2E
D - E > E - B
2D > A + C

Theorems

Properties of inequalities
Linear equation systems

Suitable Grade Level

Grades 9-12