The given expression is:

\[
n = \frac{2}{7 \times 6} + \frac{81}{2} - \frac{2}{3 \times 4}
\]

To solve this, follow these steps:

1. **Evaluate the denominators** in the fractions:
   - \( 7 \times 6 = 42 \)
   - \( 3 \times 4 = 12 \)

2. Substitute the evaluated denominators back into the expression:

\[
n = \frac{2}{42} + \frac{81}{2} - \frac{2}{12}
\]

3. Simplify the fractions:
   - \( \frac{2}{42} = \frac{1}{21} \)
   - \( \frac{2}{12} = \frac{1}{6} \)

Now the expression becomes:

\[
n = \frac{1}{21} + \frac{81}{2} - \frac{1}{6}
\]

4. Find a common denominator to combine all the fractions. The least common denominator (LCD) of 21, 2, and 6 is 42.

   - Convert \( \frac{1}{21} \) to \( \frac{2}{42} \)
   - Convert \( \frac{81}{2} \) to \( \frac{1701}{42} \)
   - Convert \( \frac{1}{6} \) to \( \frac{7}{42} \)

Now the expression becomes:

\[
n = \frac{2}{42} + \frac{1701}{42} - \frac{7}{42}
\]

5. Combine the fractions:

\[
n = \frac{2 + 1701 - 7}{42} = \frac{1696}{42}
\]

6. Simplify \( \frac{1696}{42} \):

\[
n = \frac{848}{21} \approx 40.38
\]

Thus, the value of \( n \approx 40.38 \).

Would you like more details or have any questions?

Here are 5 related questions:
1. What is the least common denominator (LCD) of 12 and 18?
2. How do you simplify the expression \( \frac{12}{36} + \frac{5}{6} \)?
3. What is the value of \( n \) in the equation \( n = \frac{3}{4} + \frac{5}{8} - \frac{2}{3} \)?
4. How can you add and subtract mixed fractions, such as \( 2 \frac{1}{3} + 4 \frac{2}{5} - 3 \frac{1}{2} \)?
5. How would you calculate the value of \( n \) in the expression \( n = 5.7 + \frac{2}{3} - \frac{1}{4} \)?

**Tip**: When adding or subtracting fractions, always find the least common denominator to simplify calculations.

Learn how to solve the complex arithmetic expression (2 / (7 * 6)) + (81 / 2) - (2 / (3 * 4)) step-by-step with detailed explanations. This problem involves fractions, arithmetic operations, and finding the least common denominator. Suitable for students in Grades 6-8.

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