Math Problem Statement

t=x/b+(2zcos(theta)/v) solve for z

Solution

We are given the equation:

t=xb+2zcos(θ)vt = \frac{x}{b} + \frac{2z \cos(\theta)}{v}

We need to solve for zz. Follow these steps:

Step 1: Subtract xb\frac{x}{b} from both sides.

txb=2zcos(θ)vt - \frac{x}{b} = \frac{2z \cos(\theta)}{v}

Step 2: Multiply both sides of the equation by vv to eliminate the denominator on the right-hand side.

v(txb)=2zcos(θ)v \left( t - \frac{x}{b} \right) = 2z \cos(\theta)

Step 3: Divide both sides by 2cos(θ)2 \cos(\theta) to solve for zz.

z=v(txb)2cos(θ)z = \frac{v \left( t - \frac{x}{b} \right)}{2 \cos(\theta)}

Thus, the solution for zz is:

z=v(txb)2cos(θ)z = \frac{v \left( t - \frac{x}{b} \right)}{2 \cos(\theta)}

Would you like more details on the steps, or do you have any questions?

Here are 5 relative questions to expand on this:

  1. How can we apply this formula in a real-world scenario?
  2. What happens to zz when θ=90\theta = 90^\circ?
  3. How does changing vv affect the value of zz?
  4. Can you explain why cos(θ)\cos(\theta) appears in the equation?
  5. How would you solve for θ\theta if zz is known?

Tip: In trigonometric equations, make sure to check whether certain angles (like 9090^\circ or 180180^\circ) make terms like cos(θ)\cos(\theta) zero, which can lead to undefined results.

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Math Problem Analysis

Mathematical Concepts

Algebra
Trigonometry

Formulas

t = x/b + (2zcos(θ)/v)
z = v(t - x/b) / (2cos(θ))

Theorems

Trigonometric Identity (Cosine Function)

Suitable Grade Level

Grades 10-12