Math Problem Statement

Find the value of x, given a right triangle with sides 10, 25, and a smaller triangle within it with sides 4 and x.

Solution

This problem involves two similar triangles within a right triangle. The smaller triangle has sides of length 4 (adjacent side) and xx (hypotenuse), while the larger triangle has sides of length 10 (adjacent side) and 25 (hypotenuse). We can use the property of similar triangles to find the value of xx.

Step-by-Step Solution:

  1. Since the triangles are similar, their corresponding sides are proportional. This gives us the ratio: 410=x25\frac{4}{10} = \frac{x}{25}

  2. Cross-multiply to solve for xx: 4×25=10×x4 \times 25 = 10 \times x 100=10x100 = 10x

  3. Divide both sides by 10 to isolate xx: x=10010=10x = \frac{100}{10} = 10

Thus, the value of xx is 10\boxed{10}.

Would you like further clarification on the method used? Here are five related questions to deepen your understanding:

  1. What is the concept of similar triangles, and how can it be used to solve for unknown sides?
  2. How do you identify corresponding sides in similar triangles?
  3. Can you explain why the two triangles in this diagram are similar?
  4. What happens if the triangles are not similar? Can you still solve for xx?
  5. How does cross-multiplication work in solving proportion equations?

Tip: In geometry, always look for similar triangles within complex shapes—they often provide a simpler way to find missing dimensions using proportional relationships.

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Math Problem Analysis

Mathematical Concepts

Geometry
Similar Triangles
Proportions

Formulas

Proportion: a/b = c/d
Cross-multiplication

Theorems

Theorem of Similar Triangles

Suitable Grade Level

Grades 8-10