Math Problem Statement
answer 1.
Solution
Let's solve the problems based on the image you uploaded.
Question 1: Find the value of .
Part (a):
- We have a right triangle with sides 3 cm, 7 cm, and cm (hypotenuse).
- By the Pythagorean Theorem:
Part (b):
- Another right triangle with sides 11 cm, 13 cm, and cm (one of the legs this time).
- Again, using the Pythagorean Theorem:
Question 2: Find the area of the innermost square.
- ABCD is a square with side length 12 cm.
- The squares are inscribed recursively within each other, forming a spiral pattern. This is likely a geometric progression where each square's side length reduces by a constant factor.
Let’s assume the reduction factor is based on the way squares are inscribed in each other at 45-degree angles (this is a common geometric relationship for inscribed squares).
- The first square has side length 12 cm.
- The second square's side is .
- Continuing with the same ratio:
- Third square: ,
- Fourth square: ,
- Fifth square (innermost): .
The area of the innermost square is:
Would you like further clarification or more details on any part? Here are some related questions for additional practice:
- What would be the length of the hypotenuse if one leg of a triangle is 6 cm and the other leg is 8 cm?
- How do you find the area of a square inscribed inside a circle?
- How can the Pythagorean theorem be applied to find the length of a diagonal in a rectangle?
- If the reduction factor for the squares was different, how would that affect the area of the innermost square?
- What is the geometric sequence of side lengths in an inscribed square problem like this one?
Tip: Always double-check your triangle sides using the Pythagorean theorem, as it's a quick way to ensure correctness when dealing with right triangles.
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Math Problem Analysis
Mathematical Concepts
Geometry
Pythagorean Theorem
Area of Squares
Geometric Progression
Formulas
Pythagorean theorem: a^2 + b^2 = c^2
Area of a square: A = side^2
Geometric progression for inscribed squares
Theorems
Pythagorean theorem
Suitable Grade Level
Grade 8-10
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