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Let's solve the equation step by step.

We are given:

\[
6x + a = 5(x + t)
\]

Our goal is to make \( x \) the subject of the formula.

### Step 1: Expand the right-hand side
Distribute the 5 on the right-hand side:

\[
6x + a = 5x + 5t
\]

### Step 2: Isolate the terms with \( x \)
Move all terms involving \( x \) to one side and the rest to the other side. Let's subtract \( 5x \) from both sides:

\[
6x - 5x + a = 5t
\]

Simplify:

\[
x + a = 5t
\]

### Step 3: Solve for \( x \)
Subtract \( a \) from both sides to isolate \( x \):

\[
x = 5t - a
\]

Thus, \( x = 5t - a \).

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Would you like further clarification on this? Let me know if you have questions or need details on any step!

### Related Questions:
1. How can you solve a similar equation where both sides have more complex terms?
2. How do you solve equations with fractions and make a variable the subject?
3. What if the equation had an exponent on \( x \)? How would you solve that?
4. How would this process change if \( t \) or \( a \) were squared?
5. Can you explain how the distributive property works in different types of equations?

**Tip:** When making a variable the subject of a formula, it's helpful to focus on isolating the variable step by step, dealing with any additions, subtractions, and distributions first.

Make x the subject of the formula 6x + a = 5(x + t)

Learn how to solve for x in the linear equation 6x + a = 5(x + t) using key algebraic concepts. This step-by-step solution shows how to isolate x using the distributive property and simple algebraic manipulation. Suitable for students in Grades 7-9.

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