https://file.aiquickdraw.com/mathbot/file/1728614680064ok1wq02o.jpg

The equation from the image is:

\[
\frac{33}{5} = \frac{132}{n}
\]

To solve for \( n \), we can cross-multiply:

\[
33 \cdot n = 132 \cdot 5
\]

Simplifying the right-hand side:

\[
33n = 660
\]

Now, solve for \( n \) by dividing both sides by 33:

\[
n = \frac{660}{33} = 20
\]

Thus, \( n = 20 \).

Would you like further details, or do you have any questions?

Here are 5 related questions you can explore:
1. What happens if we change the numbers on the right-hand side of the equation?
2. How would you solve for \( n \) if the equation were \( \frac{33}{x} = \frac{132}{n} \)?
3. Can we generalize this method for any fractions like \( \frac{a}{b} = \frac{c}{d} \)?
4. What real-life situations can be modeled by equations like this?
5. How can you check your answer after solving for \( n \)?

**Tip:** Cross-multiplication is a powerful method for solving proportions or equations involving fractions. Just remember to always simplify at the end!

Solve for n. \( \frac{33}{5} = \frac{132}{n} \)

Learn how to solve for n in the proportion \( \frac{33}{5} = \frac{132}{n} \) using cross multiplication. This algebraic problem involves concepts like proportions and the cross-multiplication method. Suitable for students in Grades 6-8.

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